Lab report Example | Topics and Well Written Essays - 250 words - 3

Lab Report Example For the second cycle, the mass of the water alone is the mass of the crucible lid and hydrate, less the mass of the crucible lid and residue after heating. That gives 22.678 – 22.455 = 0.223. Considering the fact that the second cycle represents a time when more accuracy is sought as opposed to the first cycle, the mass from the second cycle is taken for use in the establishment of the % of the water of hydration. The % of water of hydration is equal to the mass of the water of hydration alone, divided by the mass of the hydrated salt and the result multiplied by 100%. That gives, (0.223 / 0.636 ) * 100 = 4% to the nearest whole number. It is apparent that the experiment manifested that the percentage of the water of hydration is 4% as opposed to the theoretical value which is 5%. This may be attributed to the fact that there are some errors in the experiment that result from such attributes as impurities entering the reagents; zero error introduced in the measuring instruments and parallax error on the side of the personnel taking the readings from the instruments. The experiment however proved that indeed there is water of hydration in the reagent and that has weight which is shade off by heating the